document.write( "Question 131510: What are the asymptotes and intercepts of \"s%28x%29=%282x-4%29%2F%28x%5E2%2Bx-2%29\"? Show it on graph. \n" ); document.write( "
Algebra.Com's Answer #95995 by solver91311(24713)\"\" \"About 
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The equation of a vertical asymptote is in the form \"x=a\" where \"a\" is a value that would make the denominator go to zero. \r
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\n" ); document.write( "\n" ); document.write( "To find horizontal asymptotes, compare the degree of the numerator and denominator polynomials.\r
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\n" ); document.write( "\n" ); document.write( "If the degree of the denominator polynomial is greater than the degree of the numerator polynomial, the horizontal asymptote is \"y=0\", in other words, the x-axis. That's because, as x gets larger, the denominator is going to get larger much faster than the numerator and the entire fraction will tend to zero.\r
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\n" ); document.write( "\n" ); document.write( "If the degrees of the numerator and denominator are the same, then, as x gets very large, the only significant difference between the numerator and denominator will be the lead coefficients. Therefore, the horizontal asymptote is \"y=a%5Bn%5D%2Fa%5Bd%5D\" where \"a%5Bn%5D\" is the lead coefficient on the numerator polynomial and \"a%5Bd%5D\" is the lead coefficient on the denominator polynomial.\r
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\n" ); document.write( "\n" ); document.write( "If the degree of the numerator is greater than the degree of the denominator, then there is no horizontal asymptote. There is a straight line slant or skew asymptote if the degrees differ by 1 that is found by performing polynomial long division of the denominator into the numerator. The equation of the skew asymptote is the quotient obtained excluding any possible remainder.\r
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\n" ); document.write( "\n" ); document.write( "The x-intercepts are given by setting the numerator equal to zero and solving. Any zero that is also a zero of the denominator must be excluded. This is because \"a%2Fb=0\" if and only if \"a=0\" and \"b%3C%3E0\".\r
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\n" ); document.write( "\n" ); document.write( "y-intercepts are found by evaluating \"f%280%29\".\r
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\n" ); document.write( "\n" ); document.write( "Now, for your problem:
\n" ); document.write( "\"s%28x%29=%282x-4%29%2F%28x%5E2%2Bx-2%29\"?\r
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\n" ); document.write( "\n" ); document.write( "Vertical asymptotes: You need to find the zeros of the denominator polynomial:\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bx-2=0\"
\n" ); document.write( "\"%28x%2B2%29%28x-1%29=0\"
\n" ); document.write( "So the zeros are at 1 and -2, making the equations of the asymptotes \"x=1\" and \"x=-2\"\r
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\n" ); document.write( "\n" ); document.write( "Horizontal asymptotes: The degree of the denominator is 2 and the degree of the numerator is 1, therefore the horizontal asymptote is at \"y=0\"\r
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\n" ); document.write( "\n" ); document.write( "x-intercepts:\r
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\n" ); document.write( "\n" ); document.write( "\"2x-4=0\"
\n" ); document.write( "\"2x=4\"
\n" ); document.write( "\"x=2\"\r
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\n" ); document.write( "\n" ); document.write( "And the x-intercept is at (2,0)\r
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\n" ); document.write( "\n" ); document.write( "y=intercept:\r
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\n" ); document.write( "\n" ); document.write( "\"s%280%29=%282%280%29-4%29%2F%28%280%29%5E2%2B%280%29-2%29\"
\n" ); document.write( "\"s%280%29=-4%2F-2=2\"\r
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\n" ); document.write( "\n" ); document.write( "So the y-intercept is at (0,2)\r
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