document.write( "Question 131465: \"ORANGE THIRST\" IS 15% ORANGE JUICE AND \"QUENCHO\" IS 5% ORANGE JUICE. HOW MANY LITERS OF EACH SHOULD BE COMBINED IN OREDER TO GET 10LITERS OF A MIXTURE THAT IS 10% ORANGE JUICE?\r
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Algebra.Com's Answer #95987 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=amount of Orange Thirst needed \n" ); document.write( "Then 10-x=amount of Quencho needed\r \n" ); document.write( "\n" ); document.write( "Now we know that the amount of pure orange juice in the Orange Thirst (0.15x) plus the amount of pure orange juice in the Quencho (0.05(10-x)) has to equal the amount of pure orange Juice in the final mixture (0.10*10). So our equation to solve is:\r \n" ); document.write( "\n" ); document.write( "0.15x+0.05(10-x)=0.10*10 get rid of parens\r \n" ); document.write( "\n" ); document.write( "0.15x+0.5-0.05x=1 subtract 0.5 from each side \n" ); document.write( "0.15x+0.5-0.5-0.05x=1-0.5 collect like terms \n" ); document.write( "0.1x=0.5 divide both sides by 0.1 \n" ); document.write( "x=5 liters----amount of Orange Thirst needed \n" ); document.write( "10-x=10-5=5 liters-----------------------amount of Quencho needed\r \n" ); document.write( "\n" ); document.write( "CK\r \n" ); document.write( "\n" ); document.write( "0.15*5+0.05*5=0.10*10 \n" ); document.write( "0.75+0.25=1 \n" ); document.write( "1=1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |