document.write( "Question 131500: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function.\r
\n" ); document.write( "\n" ); document.write( "f(x) = -x^2 + 4x + 6
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Algebra.Com's Answer #95982 by solver91311(24713)\"\" \"About 
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The x-coordinate of the vertex of a parabola in the form \"f%28x%29=ax%5E2%2Bbx%2Bc\" is given by \"-b%2F2a\".\r
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\n" ); document.write( "\n" ); document.write( "The y-coordinate is then \"f%28-b%2F2a%29\".\r
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\n" ); document.write( "\n" ); document.write( "The line of symmetry passes through the vertex, so the equation is \"x=-b%2F2a\".\r
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\n" ); document.write( "\n" ); document.write( "The maximum or minimum is the value of the function at \"-b%2F2a\". Whether it is a maximum or minimum depends on whether the parabola opens up or down. If it is concave up (makes a valley rather than a hill), the point is a minimum, otherwise it is a maximum. You can tell which way the parabola opens by the sign on the lead coefficient. if \"a%3C0\", it is concave down, if \"a%3E0\", it is concave up, and, of course, if \"a=0\" you don't have a parabola at all.\r
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\n" ); document.write( "\n" ); document.write( "Let's look at your specific problem:\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29+=+-2x%5E2%2B4x%2B6+\"\r
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\n" ); document.write( "\n" ); document.write( "First thing to note is that \"a%3C0\", so this is a concave down parabola and the vertex is a maximum.\r
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\n" ); document.write( "\n" ); document.write( "\"-b%2F2a=-4%2F%282%28-2%29%29=1\", so the x-coordinate of the vertex is \"1\" and the equation of the line of symmetry is \"x=1\".\r
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\n" ); document.write( "\n" ); document.write( "The value of the function at \"-b%2F2a\", denoted \"f%28-b%2F2a%29\" for your problem is \"f%281%29=-2%281%29%5E2%2B4%281%29%2B6=%28-2%29%2B4%2B6=8\"\r
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\n" ); document.write( "\n" ); document.write( "So the y-coordinate of the vertex and the maximum value of f is \"8\"\r
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