document.write( "Question 131488: factor:
\n" ); document.write( "4x(squared)-49y(squared)\r
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\n" ); document.write( "4x(squared)-28x+49\r
\n" ); document.write( "\n" ); document.write( "simplify the rational expression
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Algebra.Com's Answer #95971 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Factor:
\n" ); document.write( "\"4x%5E2-49y%5E2\" This is the difference of two squares:
\n" ); document.write( "\"%282x%29%5E2-%287y%29%5E2\"
\n" ); document.write( "The difference of two squares is factored like this:
\n" ); document.write( "\"A%5E2-B%5E2+=+%28A%2BB%29%28A-B%29\" Apply this toyour problem:
\n" ); document.write( "\"%282x%29%5E2-%287y%29%5E2+=+%282x%2B7y%29%282x-7y%29\"
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\n" ); document.write( "Factor:
\n" ); document.write( "\"4x%5E2-28x%2B49\" Since the first and last terms are perfect squares: \"4x%5E2+=+%282x%29%5E2\" and \"49+=+7%5E2\", also, twice 2(7) = 28, the middle term of your equation, try:
\n" ); document.write( "\"4x%5E2-28x%2B49+=+%282x-7%29%282x-7%29\" = \"%282x-7%29%5E2\"
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