document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=131488>Question 131488</A>: <I><SPAN STYLE=\"word-break: break-all;\"> factor:<BR>\n" );
document.write( "4x(squared)-49y(squared)\r<BR>\n" );
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document.write( "factor:<BR>\n" );
document.write( "4x(squared)-28x+49\r<BR>\n" );
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document.write( "simplify the rational expression<BR>\n" );
document.write( "       1<BR>\n" );
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document.write( "    1  +   1<BR>\n" );
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document.write( "     r     x<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #95970 by </B><A HREF=/tutors/aboutme.mpl?userid=067isa><B>067isa(13)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=067isa><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=95970\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Factor<BR>\n" );
document.write( "4X^2- 49Y^2= different between two sequares.<BR>\n" );
document.write( "(2x-7y)(2x+7y)\r<BR>\n" );
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document.write( "4x^2-28x+49 (AC method is the fastest)<BR>\n" );
document.write( " AC= (4)(49)= 196<BR>\n" );
document.write( "so now we looking for two number that the sum will br 28 and the prdouct will be 28 <BR>\n" );
document.write( "here is all the factors that we can get 196 <BR>\n" );
document.write( "1.196<BR>\n" );
document.write( "2.98<BR>\n" );
document.write( "4.49<BR>\n" );
document.write( "7.28<BR>\n" );
document.write( "14.14<BR>\n" );
document.write( "from all of theses which one the sum will be 28 is this case it will be the last one 14+14=28 <BR>\n" );
document.write( "4x^2-14x-14x+49 ( we used the Ac to do the grouping now)<BR>\n" );
document.write( "2x(2x-7)-7(2X-7)= (2x-7)(2x-7)<BR>\n" );
document.write( " OR another way to solve this is by it's a perfect sequare trinomail \r<BR>\n" );
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