document.write( "Question 131449: plzzzzzzzzzzzzzzzz any one provide me the answer of this question..
\n" ); document.write( "The probability that a man will be alive in 25 years is 3/5 and that his wife will be alive in 25 years is 2/3.find the probability\r
\n" ); document.write( "\n" ); document.write( "1). both will be alive.
\n" ); document.write( "2). only the man will be alive.
\n" ); document.write( "3). only the wife will be alive.
\n" ); document.write( "4). atleast one will be alive.
\n" ); document.write( "5). neither will be alive.
\n" ); document.write( "

Algebra.Com's Answer #95966 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The probability that a man will be alive in 25 years is 3/5 and that his wife will be alive in 25 years is 2/3.find the probability
\n" ); document.write( "1). P(both will be alive) = (3/5)(2/5) = 6/25
\n" ); document.write( "2). P(only the man will be alive= (3/5)(1/3)= (1/5)
\n" ); document.write( "3). P(only the wife will be alive)=(2/5)(2/3) = 4/15
\n" ); document.write( "4). P(atleast one will be alive) = 1-P(both die) = 1-(2/5)(1/3) = 13/15
\n" ); document.write( "5). P(neither will be alive) = (2/5)(1/3) = 2/15
\n" ); document.write( "==============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" ); document.write( "
\n" );