document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=131471>Question 131471</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help putting this rational expression in lowest terms:\r<BR>\n" );
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document.write( "72x^2y^3z^5<BR>\n" );
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document.write( "240xy^3z^7            I first simplified the 72 and 240 by dividing both by 8. I think I need to factor them before finding the lowest terms, but can't figure out how to factor the different variables. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #95963 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=95963\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 72x^2y^3z^5<BR>\n" );
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document.write( "240xy^3z^7  \r<BR>\n" );
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document.write( "You don't need to factor; you only need to divide:\r<BR>\n" );
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document.write( "=(72/240)*(x^2/x)*y^3/y^3)(z^5)/(z^7)\r<BR>\n" );
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document.write( "= (3/10)*x*1*(1/z^2)\r<BR>\n" );
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document.write( "= (3x)/(10z^2) <BR>\n" );
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document.write( "=(3/10)(x/z^2)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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