document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=131408>Question 131408</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the slope of the line with the equation 2x+3y+6=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #95944 by </B><A HREF=/tutors/aboutme.mpl?userid=grmpichardo><B>grmpichardo(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=grmpichardo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=95944\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Ok. Well first you have to move the 3y to the other side so that it is isolated. That would be 2x+6=-3y<BR>\n" );
document.write( "Once you've done this you make the -3y into just 'y' by dividing everything on the other side by -3<BR>\n" );
document.write( "That would be <BR>\n" );
document.write( "  2<BR>\n" );
document.write( " —<BR>\n" );
document.write( "-3x +6=y\r<BR>\n" );
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document.write( "and whatever is in front of your X is your slope, so the slope would be 2/-3.\r<BR>\n" );
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document.write( "Hope it helped =) </SPAN>\n" );
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