document.write( "Question 131424This question is from textbook Beginnng and Intermediate Algebra
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document.write( ": The supplemet of an angle measures 10 times more than the measure of its complement. What is the measure of the angle? \n" );
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Algebra.Com's Answer #95930 by TakeATuition.com(57) ![]() You can put this solution on YOUR website! SOLUTION -\r \n" ); document.write( "\n" ); document.write( " Let the measure of an angle be x degree\r \n" ); document.write( "\n" ); document.write( " now according to the condition we have \"The supplemet of an angle measures 10 times more than the measure of its complement\"\r \n" ); document.write( "\n" ); document.write( " Therefore \n" ); document.write( " supplement of angle x = 180 - x \n" ); document.write( " complement of angle x = 90 - x \n" ); document.write( " \n" ); document.write( " 180 - x = 90 - x + 10(90 - x)\r \n" ); document.write( "\n" ); document.write( " 180 - x = 90 - x + 900 - 10x\r \n" ); document.write( "\n" ); document.write( " 180 - x - 180 = 90 - x + 900 - 10x - 180 \n" ); document.write( " \n" ); document.write( " -x + 10x = 810 - x - 10x + 10x \n" ); document.write( " \n" ); document.write( " 9x = 810 -x\r \n" ); document.write( "\n" ); document.write( " 9x + x = 810 - x + x\r \n" ); document.write( "\n" ); document.write( " 10x = 810 \n" ); document.write( " \n" ); document.write( " 10x/10 = 810/10 \n" ); document.write( " \n" ); document.write( " x = 81\r \n" ); document.write( "\n" ); document.write( " Therefore the measure of angle x = 81 degree\r \n" ); document.write( "\n" ); document.write( " FOR MORE HELP VISIT : www.TakeATuition.com \n" ); document.write( " \n" ); document.write( " |