document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=19892>Question 19892</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need your help with, Factoring Trinomials By Grouping, If the Trinomials cannot be factored write \"PRIME\"\r<BR>\n" );
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document.write( "18p^4+63p^3+27p^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #9591 by </B><A HREF=/tutors/aboutme.mpl?userid=vidyamanohar><B>vidyamanohar(13)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vidyamanohar><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=9591\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p^4, p^3, p^2 are variable terms present in the expression.  we can see p^2 is present in all the terms.\r<BR>\n" );
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document.write( "and 18, 63, 27 are the constants we see in the expression<BR>\n" );
document.write( "the common factor for all of them is 9 (Reason!!!...we see them in the 9 table)\r<BR>\n" );
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document.write( "so, we can take out 9p^2 from the expression and see <BR>\n" );
document.write( "9p^2(2p^2+7p+3)\r<BR>\n" );
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document.write( "the remaining quadratic factor can be factorized using the usual method of factorisation for quadratics<BR>\n" );
document.write( "this is how it goes\r<BR>\n" );
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document.write( "9p^2(2p^2+7p+3)=9p^2(2p^2+p+6p+3)=9p^2[p(2p+1)+3(2p+1)]=9p^2(p+3)(2p+1)\r<BR>\n" );
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document.write( "hence the factorisation over. </SPAN>\n" );
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