document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=19893>Question 19893</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need your help with, Factoring Trinomials By Grouping, If the Trinomials cannot be factored write \"PRIME\"\r<BR>\n" );
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document.write( "3x^2-7xy+6xy-14y^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #9590 by </B><A HREF=/tutors/aboutme.mpl?userid=vidyamanohar><B>vidyamanohar(13)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vidyamanohar><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=9590\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Probably this question is given half solved.\r<BR>\n" );
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document.write( "I guess the real question as to factorize 3x^2-xy-14y^2\r<BR>\n" );
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document.write( "The task now is to write the coefficient of xy (here it is -1) as the sum of two numbers whose product is exactly equal to the product of 3 and -14 (the coefficients of x^2 and y^2 respectively)\r<BR>\n" );
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document.write( "the numbers we can make out are -7 and 6 as their sum is -1 and product -42, same as the product of 3 and -14!!!\r<BR>\n" );
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document.write( "so we can write the given expression as <BR>\n" );
document.write( "3x^2+6xy-7xy-14y^2<BR>\n" );
document.write( "that gives<BR>\n" );
document.write( "3x(x+2y)-7y(x-2y)<BR>\n" );
document.write( "=(3x-7y)(x+2y)\r<BR>\n" );
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document.write( "Hence the factors are (3x-7y)and (x+2y) </SPAN>\n" );
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