document.write( "Question 131335: Use the properties of inverse functions to evaluate the expression
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document.write( "cos [arcsin (5sqrt29/29)]\r
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document.write( "I was told the answer is 2sqrt29/29 but I can't figure out how. Thanks! \n" );
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Algebra.Com's Answer #95859 by stanbon(75887) ![]() You can put this solution on YOUR website! evaluate the expression \n" ); document.write( "cos [arcsin (5sqrt29/29)]\r \n" ); document.write( "\n" ); document.write( "--------------------------------- \n" ); document.write( "Sketch a rt. triangle in standard position in the 1st Quadrant. \n" ); document.write( "You have an angle whose sine is (5sqrt(29))/29 \n" ); document.write( "So the hypotenuse is 29 and the vertical side is 5sqrt(29) \n" ); document.write( "--------------- \n" ); document.write( "Use Pythagoras to solve for the horizontal side (hs) \n" ); document.write( "(hs)^2 = 29^2 -(5sqrt(29))^2 \n" ); document.write( "(hs)^2 = 841 - 725 \n" ); document.write( "(hs) = 10.77... \n" ); document.write( "-------------------- \n" ); document.write( "Therefore cos[angle] = 10.77/29 \n" ); document.write( "=================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |