document.write( "Question 131335: Use the properties of inverse functions to evaluate the expression
\n" ); document.write( "cos [arcsin (5sqrt29/29)]\r
\n" ); document.write( "\n" ); document.write( "I was told the answer is 2sqrt29/29 but I can't figure out how. Thanks!
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Algebra.Com's Answer #95859 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
evaluate the expression
\n" ); document.write( "cos [arcsin (5sqrt29/29)]\r
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\n" ); document.write( "Sketch a rt. triangle in standard position in the 1st Quadrant.
\n" ); document.write( "You have an angle whose sine is (5sqrt(29))/29
\n" ); document.write( "So the hypotenuse is 29 and the vertical side is 5sqrt(29)
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\n" ); document.write( "Use Pythagoras to solve for the horizontal side (hs)
\n" ); document.write( "(hs)^2 = 29^2 -(5sqrt(29))^2
\n" ); document.write( "(hs)^2 = 841 - 725
\n" ); document.write( "(hs) = 10.77...
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\n" ); document.write( "Therefore cos[angle] = 10.77/29
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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