document.write( "Question 131317: the problem is: solve for x and graph on a number line. \r
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document.write( "5 - 3x > 10x - 8\r
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document.write( "i came up with X > 1\r
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document.write( "and when i graphed the problem i started at 1 (i drew the circle NOT shadded in) and drew the arrow going in the positive direction.\r
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document.write( "i can't figure out the right solution for this problem. \n" );
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Algebra.Com's Answer #95843 by solver91311(24713) You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add -5 to both sides: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add -10x to both sides: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now divide both sides by -13, but remember that if you multiply or divide both sides of an inequality by a negative number, you have to reverse the sense of the inequality. Look at an example using specific numbers:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So back to your problem: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide by -13 and turn the inequality sign around: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So your number line graph should have the open circle at 1, but the arrow needs to go to the left (in the negative direction).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, let's prove the answer with a couple of examples. 0 is less than 1, so let's substitute 0 for x into the original inequality:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2 is greater than 1, so plug in a 2: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |