document.write( "Question 19850: Let f(x)=13x^2+65x+3. Find a such that f(a)=3 \n" ); document.write( "

Algebra.Com's Answer #9583 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Did you really mean...\"Find x such that f(x) = 3\" ??\r
\n" ); document.write( "\n" ); document.write( "If $\"f%28x%29+=+13x%5E2%2B65x%2B3\"$ , then:
\n" ); document.write( " $\"f%28x%29+=+3\"$ = $\"13x%5E2+%2B+65x+%2B+3+=+3\"$ Solve for x.
\n" ); document.write( " $\"13x%5E2+%2B+65x+%2B+3+=+3\"$ Subtract 3 from both sides of the equation.
\n" ); document.write( " $\"13x%5E2+%2B+65x+=+0\"$ Factor 13x from the left side.
\n" ); document.write( " $\"13x%28x+%2B+5%29+=+0\"$ Apply the zero products principle.
\n" ); document.write( " $\"13x+=+0\"$ and/or $\"x+%2B+5+=+0\"$
\n" ); document.write( "If $\"13x+=+0\"$ then, x = 0
\n" ); document.write( "If $\"x+%2B+5+=+0\"$ then, $\"x+=+-5\"$ \r
\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( " $\"f%280%29+=+13%280%29%5E2+%2B+65%280%29+%2B+3\"$ = $\"3\"$
\n" ); document.write( " $\"f%28-5%29+=+13%28-5%29%5E2+%2B+65%28-5%29+%2B+3\"$ = $\"325+%2B+%28-325%29+%2B+3+=+3\"$ \n" ); document.write( "

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