document.write( "Question 131224This question is from textbook Algebra II
\n" ); document.write( ": 6X squared + 7X = 3
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Algebra.Com's Answer #95817 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"6x%5E2%2B7x=3\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"6x%5E2%2B7x-3=0\" Subtract 3 from both sides. \r
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\n" ); document.write( "\n" ); document.write( "\"%282x%2B3%29%283x-1%29=0\" Factor the left side (note: if you need help with factoring, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "Now set each factor equal to zero:\r
\n" ); document.write( "\n" ); document.write( "\"2x%2B3=0\" or \"3x-1=0\" \r
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\n" ); document.write( "\n" ); document.write( "\"x=-3%2F2\" or \"x=1%2F3\" Now solve for x in each case\r
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\n" ); document.write( "\n" ); document.write( "So our solutions are \r
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\n" ); document.write( "\n" ); document.write( " \"x=-3%2F2\" or \"x=1%2F3\" \r
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