document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=19811>Question 19811</A>: <I><SPAN STYLE=\"word-break: break-all;\"> jason is 1 year older than twice his bro's age. the difference of their ages is 18. find their present ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #9579 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=9579\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LEt the brother be x<BR>\n" );
document.write( "Let jason be 2x+1<BR>\n" );
document.write( "Difference = 18\r<BR>\n" );
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document.write( "(x)-(2x+1)=18<BR>\n" );
document.write( "x+1-1=18-1<BR>\n" );
document.write( "x=17<BR>\n" );
document.write( "Jason = 35 Therefore Jason is 35 and his brother is 17 </SPAN>\n" );
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