document.write( "Question 131147: one number is 6 less than a second number, twice the second number is 39 more than 5 times the second number. find the two numbers \n" ); document.write( "
Algebra.Com's Answer #95758 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! one number is 6 less than a second number, twice the second number is 39 more than 5 times the second (YOU MUST MEAN FIRST NUMBER?????) number. find the two numbers\r \n" ); document.write( "\n" ); document.write( "Let x=the second number \n" ); document.write( "Then x-6=the first number\r \n" ); document.write( "\n" ); document.write( "Now we are told that:\r \n" ); document.write( "\n" ); document.write( "2x=5(x-6)+39 get rid of parens\r \n" ); document.write( "\n" ); document.write( "2x=5x-30+39 subtract 5x from both sides \n" ); document.write( "2x-5x=5x-5x-30+39 collect like terms\r \n" ); document.write( "\n" ); document.write( "-3x=9 divide both sides by -3 \n" ); document.write( "x=-3---------------------second number\r \n" ); document.write( "\n" ); document.write( "x-6=-3-6=-9----------------------first number\r \n" ); document.write( "\n" ); document.write( "CK\r \n" ); document.write( "\n" ); document.write( "2*(-3)=5*(-9)+39 \n" ); document.write( "-6=-45+39 \n" ); document.write( "-6=-6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " |