document.write( "Question 131119: \"12%28p%2B3%29%5E2%2B13%28p%2B3%29%2B3\"
\n" ); document.write( "I can't figure out how to factor this completely the answer I keep getting is p+3(12p+52) but I don't think it is right. One of the other questions I have is
\n" ); document.write( "\"18z%5E8-15z%5E5-18z%5E2\" The answer I got to that is \"3z%5E2%283z%5E4-2%29%282z%5E2%2B3%29\" however i'm pretty sure that's wrong. If you could help me that would be great. Thanks so much
\n" ); document.write( "

Algebra.Com's Answer #95749 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Factor:
\n" ); document.write( "1) \"12%28p%2B3%29%5E2%2B13%28p%2B3%29%2B3\"
\n" ); document.write( "To make things a little easier, you can temporarily substitute another variable, say x,for (p+3), to give you:
\n" ); document.write( "\"12x%5E2%2B13x%2B3\" Factoring this trinomial, you'll get:
\n" ); document.write( "\"%283x%2B1%29%284x%2B3%29\" Now you can re-substitute the (p+3) for x, to get:
\n" ); document.write( "\"%283%28p%2B3%29%2B1%29%284%28p%2B3%29%2B3%29\" Now you simplify this expression.
\n" ); document.write( "\"%283p%2B9%2B1%29%284p%2B12%2B3%29\"
\n" ); document.write( "\"%283p%2B10%29%284p%2B15%29\" ...and there you have it!
\n" ); document.write( "---------------------------------------------
\n" ); document.write( "Check:
\n" ); document.write( "Let's first multiply the factors using FOIL:
\n" ); document.write( "\"%283p%2B10%29%284p%2B15%29+=+12p%5E2%2B45p%2B40p%2B150\" = \"12p%5E2%2B85p%2B150\"
\n" ); document.write( "Now we'll expand the given trinomial that you were asked to factor:
\n" ); document.write( "\"12%28p%2B3%29%5E2%2B13%28p%2B3%29%2B3+=+12%28p%5E2%2B6p%2B9%29%2B13%28p%2B3%29%2B3\" = \"%2812p%5E2%2B72p%2B108%29%2B%2813p%2B39%29%2B3+=+12p%5E2%2B85p%2B150\"\r
\n" ); document.write( "\n" ); document.write( "2) Factor:
\n" ); document.write( "\"18z%5E8-15z%5E5-18z%5E2\" First factor \"3z%5E2\"
\n" ); document.write( "\"3z%5E2%286z%5E6-5z%5E3-18%29\" Now, to simplify the calculations a bit, temporarily substitute x for \"z%5E3\", but only inside the parentheses!
\n" ); document.write( "\"3z%5E2%286x%5E2-5x-6%29\" Now factor the trinomial in x.
\n" ); document.write( "\"3z%5E2%283x%2B2%29%282x-3%29\" Finally, you can replace the x with \"z%5E3\"
\n" ); document.write( "\"3z%5E2%283z%5E3%2B2%29%282z%5E3-3%29\" ...so you were close!
\n" ); document.write( "------------------------------
\n" ); document.write( "Check:
\n" ); document.write( "\"3z%5E2%283z%5E3%2B2%29%282z%5E3-3%29+=+3z%5E2%286z%5E6-9z%5E3%2B4z%5E3-6%29\" = \"3z%5E2%286z%5E6-5z%5E3-6%29+=+18z%5E8-15z%5E5-18z%5E2\"...which is exactly what you started with!
\n" ); document.write( "
\n" );