document.write( "Question 130977: I need help with this question.\r
\n" ); document.write( "\n" ); document.write( "Question: The temperature recorded by a certain thermometer when placed in boiling water (true temperature 100 degree C) is normally distributed with mean μ = 99.8 degree C and standard deviation σ = 0.1 degree C. [Please draw a density curve before you do any calculations.]\r
\n" ); document.write( "\n" ); document.write( "1). What is the probability that the thermometer reading is greater than 100 degree C?\r
\n" ); document.write( "\n" ); document.write( "2). What is the probability that the thermometer reading is exactly 100 degree C?\r
\n" ); document.write( "\n" ); document.write( "3). What is the probability that the thermometer reading is within ± 0.05 degree C?
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Algebra.Com's Answer #95747 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The temperature recorded by a certain thermometer when placed in boiling water (true temperature 100 degree C) is normally distributed with mean μ = 99.8 degree C and standard deviation σ = 0.1 degree C. [Please draw a density curve before you do any calculations.]
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\n" ); document.write( "Draw a normal curve; put mean = 99.8.
\n" ); document.write( "Calculate the z-value of the termperature in each of the problems using
\n" ); document.write( "z(x) = (x-mu)/sigma
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\n" ); document.write( "1). What is the probability that the thermometer reading is greater than 100 degree C?
\n" ); document.write( "z(100) = (100-99.8)/0.1 = 0.02/0.1 = 0.2
\n" ); document.write( "P(z>0.2) = 0.4207
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\n" ); document.write( "2). What is the probability that the thermometer reading is exactly 100 degree C?
\n" ); document.write( "The probability of any particular value is zero
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\n" ); document.write( "3). What is the probability that the thermometer reading is within ± 0.05 degree C?
\n" ); document.write( "I'll assume you mean within 0.05 degrees of the mean.
\n" ); document.write( "Find the z-value of 99.8+0.05= 99.85
\n" ); document.write( "z(99.85) = (99.85-99.8)/0.1 = 0.5
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\n" ); document.write( "P(99.8-0.05 < temp < 99.5+0.05) = P(-0.5 < z < 0.5) = 0.3829
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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