document.write( "Question 131089This question is from textbook Prealgebra and Introductory Algebra
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document.write( ": 7/20+3/8+4/5 \n" );
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Algebra.Com's Answer #95714 by fners(16)![]() ![]() ![]() You can put this solution on YOUR website! You need to make all the denominators (bottom numbers) match before you can add.\r \n" ); document.write( "\n" ); document.write( "(7/20)*(8/8)= 56/160 \n" ); document.write( "(3/8)*(20/20)= 60/160 \n" ); document.write( "(4/5)*(32/32)= 128/160\r \n" ); document.write( "\n" ); document.write( "(56+60+128)/160= 244/160\r \n" ); document.write( "\n" ); document.write( "(8/8 is equal to 1, so you can multiply any number by it without changing the number. same with 2/20, 32/32, etc.)\r \n" ); document.write( "\n" ); document.write( "To reduce, try dividing both the numerator and denominator by 2:\r \n" ); document.write( "\n" ); document.write( "122/80\r \n" ); document.write( "\n" ); document.write( "both numbers are still even, so you can do it again:\r \n" ); document.write( "\n" ); document.write( "81/40\r \n" ); document.write( "\n" ); document.write( "can you think of any number that is a factor of both 81 and 40?\r \n" ); document.write( "\n" ); document.write( "i can't, so we are done. The answer is reduced. \n" ); document.write( " |