document.write( "Question 130980: At Ajax Spring Water, a 1/2 liter bottle of soft drink is supposed to contain a mean of 520 ml. The filling process follows a normal distribution with a known process standard deviation of 4 ml. (A) which sampling distribution would you use if random samples of 10 bottles are to be weighed? Why?
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document.write( "(B) Set up hypotheses and a twotailed decision rult for the correct mean using the 5 percent level of significance. (C) If a sample of 16 bottles shows a mean fill of 515 ml, does that contradict the hypothesis that the true mean is 520ml? \n" );
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Algebra.Com's Answer #95703 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! At Ajax Spring Water, a 1/2 liter bottle of soft drink is supposed to contain a mean of 520 ml. The filling process follows a normal distribution with a known process standard deviation of 4 ml. \n" ); document.write( "---------------------------- \n" ); document.write( "(A) which sampling distribution would you use if random samples of 10 bottles are to be weighed? Why? \n" ); document.write( "The t-distribution which is suitable for small-sample testing. \n" ); document.write( "---------------------------- \n" ); document.write( "(B) Set up hypotheses and a twotailed decision rule for the correct mean using the 5 percent level of significance. \n" ); document.write( "Ho: mu = 520 \n" ); document.write( "Ha: mu is not equal to 520 \n" ); document.write( "Critical values for alpha = 5% and 9 degrees of freedom : t = +-1.833 \n" ); document.write( "---------------------------- \n" ); document.write( "(C) If a sample of 16 bottles shows a mean fill of 515 ml, does that contradict the hypothesis that the true mean is 520ml? \n" ); document.write( "Critical values for alpha=5% and 15 degrees of freedom : t= +-1.753 \n" ); document.write( "Test statistic: t(515)=(515-520)/[4/sqrt(16)]=-5*4/4 = -5 \n" ); document.write( "Conclusion: Since -5 < -1.753, reject Ho; this contradicts the hypothesis \n" ); document.write( "that the true mean is 520 ml. \n" ); document.write( "=============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "---------------------------- \n" ); document.write( " \n" ); document.write( " |