document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=130912>Question 130912</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the sum of the infinite series.  If the series does not have a sum write \"no sum\".  The series is:\r<BR>\n" );
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document.write( "9 - 3 + 1 - 1/3 + 1/9. . . \r<BR>\n" );
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document.write( "I am not sure where I got n/3 from but seem to think it has something to do with solving this.<BR>\n" );
document.write( "Thanks so much for your help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #95698 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=95698\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THE SUM OF AN INFINITE SERIERS IS:<BR>\n" );
document.write( "S=A/(1-R) WHERE A=THE FIRST TERM & R=THE RATIO.<BR>\n" );
document.write( "S=9/[1-(-1/3)]<BR>\n" );
document.write( "S=9/(1+1/3)<BR>\n" );
document.write( "S=9/(4/3)<BR>\n" );
document.write( "S=9(3/4)<BR>\n" );
document.write( "S=27/4<BR>\n" );
document.write( "S=6.75 ANSWER. </SPAN>\n" );
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