document.write( "Question 19788: An afternoon sightseeing cruise up river and back down river is schedualed to last 1 hour. The speed of the current is 4kh/h, and the speed of the riverboat in still water is 12km/h. How far upstream should the pilot travel before turning around? \n" ); document.write( "
Algebra.Com's Answer #9568 by xcentaur(357)\"\" \"About 
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total time alloted is 1 hour
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\n" ); document.write( "speed of the current=4 kmph
\n" ); document.write( "speed of the boat=12 kmph
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\n" ); document.write( "Upstream:
\n" ); document.write( "let the distance be x
\n" ); document.write( "speed=12-4 (since the boat and current will be in opposite directions)
\n" ); document.write( "=8 kmph
\n" ); document.write( "time=distance/speed=(x/8)hour
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\n" ); document.write( "Downstream:
\n" ); document.write( "the distance will be equal to the distance it goes upstream
\n" ); document.write( "so distance=x
\n" ); document.write( "speed=12+4 (since boat and current will both be in the same direction)
\n" ); document.write( "=16 kmph
\n" ); document.write( "time=distance/speed=(x/16)hour
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\n" ); document.write( "total time=(time upstream)+(time downstream)
\n" ); document.write( "1=(x/8)+(x/16)
\n" ); document.write( "1=(2x+x)/16
\n" ); document.write( "1=3x/16
\n" ); document.write( "16=3x
\n" ); document.write( "x=16/3 km
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\n" ); document.write( "so he should go (16/3)km before turning around
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\n" ); document.write( "Hope this helps,
\n" ); document.write( "Prabhat \n" ); document.write( "

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