document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=131037>Question 131037</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If you cut out the largest possible circular pie crust from a square piece of dough that is d inches on a side, what is the area of the remaining dough? \r<BR>\n" );
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document.write( "If you take this remaining dough and reshape it into a new circle to make a second pie, what is the diameter of the second pie?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #95678 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=95678\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D^2=THE AREA OF THE SQUARE.<BR>\n" );
document.write( "D^2-PI(D/2)^2 IS THE AMOUNT LEFT OVER AFTER CUTTING OUT THE CIRCLE OR THE AREA OF THE NEW CIRCLE.<BR>\n" );
document.write( "[D^2-PI(D/2)^2]=PI(d/2)^2 {d being the diameter of the smaller left over pie}<BR>\n" );
document.write( "[D^2-PI(D/2)^2]/PI=(d/2)^2<BR>\n" );
document.write( "d/2=SQRT{[D^2-PI(D/2)^2]/PI}<BR>\n" );
document.write( "d=2SQRT{[D^2-PI(D/2)^2]/PI} ANSWER FOR THE DIAMETER OF THE SECOND PIE.\r<BR>\n" );
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