document.write( "Question 131046: given p(x) = -x^2-x^3+10x, find p(-1) \n" ); document.write( "
Algebra.Com's Answer #95660 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"p%28x%29=-1x%5E2-1x%5E3%2B10x\" Start with the given function\r
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\n" ); document.write( "\n" ); document.write( "\"p%28-1%29=-1%28-1%29%5E2-1%28-1%29%5E3%2B10%28-1%29\" Plug in \"x=-1\"\r
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\n" ); document.write( "\n" ); document.write( "\"p%28-1%29=-1%2A1-1%2A-1%5E3%2B10%2A-1\" Raise -1 to the 2nd power to get 1\r
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\n" ); document.write( "\n" ); document.write( "\"p%28-1%29=-1-1%2A-1%5E3%2B10%2A-1\" Multiply -1 and 1 to get -1\r
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\n" ); document.write( "\n" ); document.write( "\"p%28-1%29=-1-1%2A-1%2B10%2A-1\" Raise -1 to the 3rd power to get -1\r
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\n" ); document.write( "\n" ); document.write( "\"p%28-1%29=-1--1%2B10%2A-1\" Multiply 1 and -1 to get -1\r
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\n" ); document.write( "\n" ); document.write( "\"p%28-1%29=0%2B10%2A-1\" Subtract -1 from -1 to get 0\r
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\n" ); document.write( "\n" ); document.write( "\"p%28-1%29=0%2B-10\" Multiply 10 and -1 to get -10\r
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\n" ); document.write( "\n" ); document.write( "\"p%28-1%29=-10\" Add 0 and -10 to get -10
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