document.write( "Question 131051: factor completely: 6y^3+11y^2-35y \n" ); document.write( "
Algebra.Com's Answer #95654 by Earlsdon(6294)\"\" \"About 
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Factor:
\n" ); document.write( "\"6y%5E3%2B11y%5E2-35y\" First, factor a y.
\n" ); document.write( "\"y%286y%5E2%2B11y-35%29\" Now factor the trinomial.
\n" ); document.write( "\"y%282y%2B7%29%283y-5%29\"
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