document.write( "Question 131049: find one of the factors of: y^2+3y-40 \n" ); document.write( "
Algebra.Com's Answer #95653 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Looking at \"1y%5E2%2B3y-40\" we can see that the first term is \"1y%5E2\" and the last term is \"-40\" where the coefficients are 1 and -40 respectively.\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient 1 and the last coefficient -40 to get -40. Now what two numbers multiply to -40 and add to the middle coefficient 3? Let's list all of the factors of -40:\r
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\n" ); document.write( "\n" ); document.write( "Factors of -40:\r
\n" ); document.write( "\n" ); document.write( "1,2,4,5,8,10,20,40\r
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\n" ); document.write( "\n" ); document.write( "-1,-2,-4,-5,-8,-10,-20,-40 ...List the negative factors as well. This will allow us to find all possible combinations\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to -40\r
\n" ); document.write( "\n" ); document.write( "(1)*(-40)\r
\n" ); document.write( "\n" ); document.write( "(2)*(-20)\r
\n" ); document.write( "\n" ); document.write( "(4)*(-10)\r
\n" ); document.write( "\n" ); document.write( "(5)*(-8)\r
\n" ); document.write( "\n" ); document.write( "(-1)*(40)\r
\n" ); document.write( "\n" ); document.write( "(-2)*(20)\r
\n" ); document.write( "\n" ); document.write( "(-4)*(10)\r
\n" ); document.write( "\n" ); document.write( "(-5)*(8)\r
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\n" ); document.write( "\n" ); document.write( "note: remember, the product of a negative and a positive number is a negative number\r
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\n" ); document.write( "\n" ); document.write( "Now which of these pairs add to 3? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 3\r
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First NumberSecond NumberSum
1-401+(-40)=-39
2-202+(-20)=-18
4-104+(-10)=-6
5-85+(-8)=-3
-140-1+40=39
-220-2+20=18
-410-4+10=6
-58-5+8=3
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\n" ); document.write( "\n" ); document.write( "From this list we can see that -5 and 8 add up to 3 and multiply to -40\r
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\n" ); document.write( "\n" ); document.write( "Now looking at the expression \"1y%5E2%2B3y-40\", replace \"3y\" with \"-5y%2B8y\" (notice \"-5y%2B8y\" adds up to \"3y\". So it is equivalent to \"3y\")\r
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\n" ); document.write( "\n" ); document.write( "\"1y%5E2%2Bhighlight%28-5y%2B8y%29%2B-40\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's factor \"1y%5E2-5y%2B8y-40\" by grouping:\r
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\n" ); document.write( "\n" ); document.write( "\"%281y%5E2-5y%29%2B%288y-40%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"y%28y-5%29%2B8%28y-5%29\" Factor out the GCF of \"y\" out of the first group. Factor out the GCF of \"8\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%28y%2B8%29%28y-5%29\" Since we have a common term of \"y-5\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"1y%5E2-5y%2B8y-40\" factors to \"%28y%2B8%29%28y-5%29\"\r
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\n" ); document.write( "\n" ); document.write( "So this also means that \"1y%5E2%2B3y-40\" factors to \"%28y%2B8%29%28y-5%29\" (since \"1y%5E2%2B3y-40\" is equivalent to \"1y%5E2-5y%2B8y-40\")\r
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\n" ); document.write( "\n" ); document.write( " Answer:\r
\n" ); document.write( "\n" ); document.write( "So \"y%5E2%2B3y-40\" factors to \"%28y%2B8%29%28y-5%29\" which means that one of factors are either \"y%2B8\" or \"y-5\"
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