document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=131044>Question 131044</A>: <I><SPAN STYLE=\"word-break: break-all;\">    <BR>\n" );
document.write( "           x+7     37   x-2 <BR>\n" );
document.write( "           ___  =  __ - ____<BR>\n" );
document.write( "           3       15    5\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #95650 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=95650\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x+7)/3=37/15-(x-2)/5<BR>\n" );
document.write( "First you need to find a common denominator so you can combine these fractions.<BR>\n" );
document.write( "15 has both 3 & 5 as factors so we'll use 15.<BR>\n" );
document.write( "[5(x+7)/15]=[(37-3(x-2)/15] <BR>\n" );
document.write( "(5x+35)/15=(37-3x+6)/15<BR>\n" );
document.write( "Now we can cancel out the denominators & set the numerators equal:<BR>\n" );
document.write( "5x+35=37-3x+6<BR>\n" );
document.write( "5x+3x=37+6-35<BR>\n" );
document.write( "8x=8<BR>\n" );
document.write( "x=8/8<BR>\n" );
document.write( "x=1 answer.<BR>\n" );
document.write( "proof:<BR>\n" );
document.write( "(1+7)/3=37/15-(1-2)/5<BR>\n" );
document.write( "8/3=37/15-(-1/5)<BR>\n" );
document.write( "8/3=37/15+1/5<BR>\n" );
document.write( "8*5/15=37/15+3/15<BR>\n" );
document.write( "40/15=(37+30/15<BR>\n" );
document.write( "40/15=40/15<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );