document.write( "Question 131011: 3a^2+12ab+12b^2 can you show me how this is done completely
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Algebra.Com's Answer #95633 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
# 1\r
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\n" ); document.write( "\n" ); document.write( "\"3a%5E2%2B12ab%2B12b%5E2\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"3%28a%5E2%2B4ab%2B4b%5E2%29\" Factor out the GCF \"3\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's focus on the inner expression \"a%5E2%2B4ab%2B4b%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Looking at \"1a%5E2%2B4ab%2B4b%5E2\" we can see that the first term is \"1a%5E2\" and the last term is \"4b%5E2\" where the coefficients are 1 and 4 respectively.\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient 1 and the last coefficient 4 to get 4. Now what two numbers multiply to 4 and add to the middle coefficient 4? Let's list all of the factors of 4:\r
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\n" ); document.write( "\n" ); document.write( "Factors of 4:\r
\n" ); document.write( "\n" ); document.write( "1,2\r
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\n" ); document.write( "\n" ); document.write( "-1,-2 ...List the negative factors as well. This will allow us to find all possible combinations\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to 4\r
\n" ); document.write( "\n" ); document.write( "1*4\r
\n" ); document.write( "\n" ); document.write( "2*2\r
\n" ); document.write( "\n" ); document.write( "(-1)*(-4)\r
\n" ); document.write( "\n" ); document.write( "(-2)*(-2)\r
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\n" ); document.write( "\n" ); document.write( "note: remember two negative numbers multiplied together make a positive number\r
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\n" ); document.write( "\n" ); document.write( "Now which of these pairs add to 4? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 4\r
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First NumberSecond NumberSum
141+4=5
222+2=4
-1-4-1+(-4)=-5
-2-2-2+(-2)=-4
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\n" ); document.write( "\n" ); document.write( "From this list we can see that 2 and 2 add up to 4 and multiply to 4\r
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\n" ); document.write( "\n" ); document.write( "Now looking at the expression \"1a%5E2%2B4ab%2B4b%5E2\", replace \"4ab\" with \"2ab%2B2ab\" (notice \"2ab%2B2ab\" adds up to \"4ab\". So it is equivalent to \"4ab\")\r
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\n" ); document.write( "\n" ); document.write( "\"1a%5E2%2Bhighlight%282ab%2B2ab%29%2B4b%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's factor \"1a%5E2%2B2ab%2B2ab%2B4b%5E2\" by grouping:\r
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\n" ); document.write( "\n" ); document.write( "\"%281a%5E2%2B2ab%29%2B%282ab%2B4b%5E2%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"a%28a%2B2b%29%2B2b%28a%2B2b%29\" Factor out the GCF of \"a\" out of the first group. Factor out the GCF of \"2b\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%28a%2B2b%29%28a%2B2b%29\" Since we have a common term of \"a%2B2b\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"1a%5E2%2B2ab%2B2ab%2B4b%5E2\" factors to \"%28a%2B2b%29%28a%2B2b%29\"\r
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\n" ); document.write( "\n" ); document.write( "So this also means that \"1a%5E2%2B4ab%2B4b%5E2\" factors to \"%28a%2B2b%29%28a%2B2b%29\" (since \"1a%5E2%2B4ab%2B4b%5E2\" is equivalent to \"1a%5E2%2B2ab%2B2ab%2B4b%5E2\")\r
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\n" ); document.write( "\n" ); document.write( "note: \"%28a%2B2b%29%28a%2B2b%29\" is equivalent to \"%28a%2B2b%29%5E2\" since the term \"a%2B2b\" occurs twice. So \"1a%5E2%2B4ab%2B4b%5E2\" also factors to \"%28a%2B2b%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "So our expression goes from \"3%28a%5E2%2B4ab%2B4b%5E2%29\" and factors further to \"3%28a%2B2b%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "So \"3a%5E2%2B12ab%2B12b%5E2\" factors to \"3%28a%2B2b%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Looking at \"8x%5E2-26x-15\" we can see that the first term is \"8x%5E2\" and the last term is \"-15\" where the coefficients are 8 and -15 respectively.\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient 8 and the last coefficient -15 to get -120. Now what two numbers multiply to -120 and add to the middle coefficient -26? Let's list all of the factors of -120:\r
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\n" ); document.write( "\n" ); document.write( "Factors of -120:\r
\n" ); document.write( "\n" ); document.write( "1,2,3,4,5,6,8,10,12,15,20,24,30,40,60,120\r
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\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-4,-5,-6,-8,-10,-12,-15,-20,-24,-30,-40,-60,-120 ...List the negative factors as well. This will allow us to find all possible combinations\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to -120\r
\n" ); document.write( "\n" ); document.write( "(1)*(-120)\r
\n" ); document.write( "\n" ); document.write( "(2)*(-60)\r
\n" ); document.write( "\n" ); document.write( "(3)*(-40)\r
\n" ); document.write( "\n" ); document.write( "(4)*(-30)\r
\n" ); document.write( "\n" ); document.write( "(5)*(-24)\r
\n" ); document.write( "\n" ); document.write( "(6)*(-20)\r
\n" ); document.write( "\n" ); document.write( "(8)*(-15)\r
\n" ); document.write( "\n" ); document.write( "(10)*(-12)\r
\n" ); document.write( "\n" ); document.write( "(-1)*(120)\r
\n" ); document.write( "\n" ); document.write( "(-2)*(60)\r
\n" ); document.write( "\n" ); document.write( "(-3)*(40)\r
\n" ); document.write( "\n" ); document.write( "(-4)*(30)\r
\n" ); document.write( "\n" ); document.write( "(-5)*(24)\r
\n" ); document.write( "\n" ); document.write( "(-6)*(20)\r
\n" ); document.write( "\n" ); document.write( "(-8)*(15)\r
\n" ); document.write( "\n" ); document.write( "(-10)*(12)\r
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\n" ); document.write( "\n" ); document.write( "note: remember, the product of a negative and a positive number is a negative number\r
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\n" ); document.write( "\n" ); document.write( "Now which of these pairs add to -26? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -26\r
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First NumberSecond NumberSum
1-1201+(-120)=-119
2-602+(-60)=-58
3-403+(-40)=-37
4-304+(-30)=-26
5-245+(-24)=-19
6-206+(-20)=-14
8-158+(-15)=-7
10-1210+(-12)=-2
-1120-1+120=119
-260-2+60=58
-340-3+40=37
-430-4+30=26
-524-5+24=19
-620-6+20=14
-815-8+15=7
-1012-10+12=2
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\n" ); document.write( "\n" ); document.write( "From this list we can see that 4 and -30 add up to -26 and multiply to -120\r
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\n" ); document.write( "\n" ); document.write( "Now looking at the expression \"8x%5E2-26x-15\", replace \"-26x\" with \"4x%2B-30x\" (notice \"4x%2B-30x\" adds up to \"-26x\". So it is equivalent to \"-26x\")\r
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\n" ); document.write( "\n" ); document.write( "\"8x%5E2%2Bhighlight%284x%2B-30x%29%2B-15\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's factor \"8x%5E2%2B4x-30x-15\" by grouping:\r
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\n" ); document.write( "\n" ); document.write( "\"%288x%5E2%2B4x%29%2B%28-30x-15%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"4x%282x%2B1%29-15%282x%2B1%29\" Factor out the GCF of \"4x\" out of the first group. Factor out the GCF of \"-15\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%284x-15%29%282x%2B1%29\" Since we have a common term of \"2x%2B1\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"8x%5E2%2B4x-30x-15\" factors to \"%284x-15%29%282x%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "So this also means that \"8x%5E2-26x-15\" factors to \"%284x-15%29%282x%2B1%29\" (since \"8x%5E2-26x-15\" is equivalent to \"8x%5E2%2B4x-30x-15\")\r
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\n" ); document.write( "\n" ); document.write( "So \"8x%5E2-26x-15\" factors to \"%284x-15%29%282x%2B1%29\"
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