document.write( "Question 130984: I have having great difficulty with these worded problems; your help would be greatly appreciated. Thank you.
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document.write( "It asks me:
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document.write( "To solve the following word problem using quadratic equation:
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document.write( "Then goes on to state: \r
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document.write( "Given the area of a rectangle is 90m2 and the perimeter of the rectangle is 40m, find the breadth of the rectangle.\r
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document.write( " Thank you.
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document.write( "Anthony
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Algebra.Com's Answer #95628 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! XY=90 OR Y=90/X \n" ); document.write( "2X+2Y=40 NOW REPLACE Y WITH(90/X) \n" ); document.write( "2X+2(90/X)=40 \n" ); document.write( "2X+180/X=40 \n" ); document.write( "(2X^2+180)/X=40 \n" ); document.write( "2X^2+180=40X \n" ); document.write( "2X^2-40X+180=0 \n" ); document.write( "2(X^2-20X+90)=0 \n" ); document.write( "USING THE QUADRATIC EQUATION WE GET: \n" ); document.write( " \n" ); document.write( "X=(20+-SQRT[-20^2-4*1*90])/2*1 \n" ); document.write( "X=(20+-SQRT[400-360])/2 \n" ); document.write( "X=(20+-SQRT40)/2 \n" ); document.write( "X=(20+-6.32)/2 \n" ); document.write( "X=(20+6.32)/2 \n" ); document.write( "X=26.32/2 \n" ); document.write( "X=13.16 ANSWER. \n" ); document.write( "X=(20-6.32)/2 \n" ); document.write( "X=13.68/2 \n" ); document.write( "X=6.84 ANSWER.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |