document.write( "Question 130984: I have having great difficulty with these worded problems; your help would be greatly appreciated. Thank you.
\n" ); document.write( "It asks me:
\n" ); document.write( "To solve the following word problem using quadratic equation:
\n" ); document.write( "Then goes on to state: \r
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\n" ); document.write( "\n" ); document.write( "Given the area of a rectangle is 90m2 and the perimeter of the rectangle is 40m, find the breadth of the rectangle.\r
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\n" ); document.write( "\n" ); document.write( " Thank you.
\n" ); document.write( "Anthony
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Algebra.Com's Answer #95628 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
XY=90 OR Y=90/X
\n" ); document.write( "2X+2Y=40 NOW REPLACE Y WITH(90/X)
\n" ); document.write( "2X+2(90/X)=40
\n" ); document.write( "2X+180/X=40
\n" ); document.write( "(2X^2+180)/X=40
\n" ); document.write( "2X^2+180=40X
\n" ); document.write( "2X^2-40X+180=0
\n" ); document.write( "2(X^2-20X+90)=0
\n" ); document.write( "USING THE QUADRATIC EQUATION WE GET:
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "X=(20+-SQRT[-20^2-4*1*90])/2*1
\n" ); document.write( "X=(20+-SQRT[400-360])/2
\n" ); document.write( "X=(20+-SQRT40)/2
\n" ); document.write( "X=(20+-6.32)/2
\n" ); document.write( "X=(20+6.32)/2
\n" ); document.write( "X=26.32/2
\n" ); document.write( "X=13.16 ANSWER.
\n" ); document.write( "X=(20-6.32)/2
\n" ); document.write( "X=13.68/2
\n" ); document.write( "X=6.84 ANSWER.\r
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