document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=130928>Question 130928</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A car and a train leave station A at the same time for station B, 300 miles away. If the speed of the car averages twice the speed of the train and the car arrives 7.5 hours before the train, find the speed of the car and the speed of the train in miles per hour.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #95609 by </B><A HREF=/tutors/aboutme.mpl?userid=TakeATuition.com><B>TakeATuition.com(57)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=TakeATuition.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.takeatuition.com/images/logo.jpg valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=95609\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solution - <BR>\n" );
document.write( "  Let the speed of the car be x miles/hour<BR>\n" );
document.write( "  and the speed of train be y miles/hour<BR>\n" );
document.write( "  According to first condition<BR>\n" );
document.write( "  that is speed of the car is twice the speed of the train<BR>\n" );
document.write( "   x = 2y       ..... (i)<BR>\n" );
document.write( "  According to the second condition <BR>\n" );
document.write( "  time taken by car to cover 300 miles = distance/speed<BR>\n" );
document.write( "                                       = 300/x<BR>\n" );
document.write( "  time taken by train to cover 300 miles = 300/y<BR>\n" );
document.write( "  now car arrives 7.5 hours before train<BR>\n" );
document.write( "  therefore<BR>\n" );
document.write( "         300/x + 7.5 = 300/y  (since train takes 7.5 hours more than car therefore we will add 7.5 hours with the time of the car to equate the value)<BR>\n" );
document.write( "    now substituting the value of x from equation (i) we have<BR>\n" );
document.write( "        300/2y +7.5 = 300/y<BR>\n" );
document.write( " now transfering the like terms on one side we have<BR>\n" );
document.write( " 7.5 = 300/y - 300/2y<BR>\n" );
document.write( "  75/10 = (600 - 300)/2y<BR>\n" );
document.write( "   75/10 = 300/2y<BR>\n" );
document.write( "   15/2 = 150/y<BR>\n" );
document.write( " now by cross multiplicationb we have<BR>\n" );
document.write( "  15y = 300<BR>\n" );
document.write( "    y = 300/15<BR>\n" );
document.write( "    y = 20<BR>\n" );
document.write( " now substituting the value of y in equation (i) we have<BR>\n" );
document.write( "    x = 2y<BR>\n" );
document.write( "    x = 2*20<BR>\n" );
document.write( "    x = 40<BR>\n" );
document.write( " therefore the speed of the train is y miles/hour = 20 miles/hour<BR>\n" );
document.write( "  and speed of car is x miles/hour = 40 miles/hour<BR>\n" );
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