document.write( "Question 130899This question is from textbook ALGEBRA FOR COLLEGE STUDENTS MARK DUGOPOLSKI
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document.write( ": To make ends meet, Ms. Farnsby works three jobs. Her total income last year was $48,000. Her income from teaching was just $6,000 more than her income from house painting. Royalties from her text book sales were one-seventh of the total money she recieved from teaching and house painting. HOw much did she make from each source last year? \n" );
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Algebra.Com's Answer #95608 by edjones(8007)![]() ![]() You can put this solution on YOUR website! Let t=income from teaching, p=income from painting, b=income from book sales. \n" ); document.write( "t=p+6000 \n" ); document.write( "b=(t+p)/7 \n" ); document.write( "b+t+p=48000 \n" ); document.write( "(t+p)/7 +p+6000+p=48000 substitute \n" ); document.write( "(p+6000+p)/7 + p+6000 + p = 48000 more substitution \n" ); document.write( "(2p+6000)/7 + p+6000 + p = 48000 \n" ); document.write( "(2p+6000) + 7(p+6000) + 7p = 7*48000 multiply each side by 7 to eliminate the fraction. \n" ); document.write( "2p+6000+7p+42000+7p=336000 \n" ); document.write( "16p+48000=336000 \n" ); document.write( "16p=336000-48000 \n" ); document.write( "16p=288000 \n" ); document.write( "16p/16=288000/16 \n" ); document.write( "p=$18,000. \n" ); document.write( ". \n" ); document.write( "t=18000+6000 \n" ); document.write( "t=$24,000. \n" ); document.write( ". \n" ); document.write( "b=(24000+18000)/7 \n" ); document.write( "=42000/7 \n" ); document.write( "=$6000. \n" ); document.write( ". \n" ); document.write( "Ed\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |