document.write( "Question 130881This question is from textbook algebra 1
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document.write( ": An airplane flew for 5 hours with a tail wine of 25 kph. The return flight against the same wind took 5.5 hours. Find the speed of the airplane in still air. \n" );
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Algebra.Com's Answer #95571 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 5(X+25)=5.5(X-25) \n" ); document.write( "5X+125=5.5X-137.5 \n" ); document.write( "5X-5.5X=-137.5-125 \n" ); document.write( "-.5X=-262.5 \n" ); document.write( "X=-262.5/.5 \n" ); document.write( "X=525 ANSWER FOR THE SPEED OF THE PLANE IN STILL AIR. \n" ); document.write( "PROOF: \n" ); document.write( "5(525+25)=5.5(525-25) \n" ); document.write( "5*550=5.5*500 \n" ); document.write( "2750=2750\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |