document.write( "Question 130884:
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document.write( "JANE IS THREE TIMES AS OLD AS HER SISTER. IN THREE YEARS, SHE WILL BE 2 YEARS MORE THAN TWICE OF HER SISTER'S AGE. WHAT ARE THEIR PRESENT AGE? THANK U VERY MUCH... \n" );
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Algebra.Com's Answer #95570 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! JANE=3X \n" ); document.write( "SISTER=X \n" ); document.write( "(3X+3)=2(X+3)+2 \n" ); document.write( "3X+3=2X+6+2 \n" ); document.write( "3X-2X=6+2-3 \n" ); document.write( "X=5 AGE OF THE SISTER NOW. \n" ); document.write( "3*5=15 JANE'S AGE NOW.PROOF: \n" ); document.write( "(3*5+3)=2(5+3)+2 \n" ); document.write( "15+3=2*8+2 \n" ); document.write( "18=16+2 \n" ); document.write( "18=18 \n" ); document.write( " \n" ); document.write( " |