document.write( "Question 130884:
\n" ); document.write( "JANE IS THREE TIMES AS OLD AS HER SISTER. IN THREE YEARS, SHE WILL BE 2 YEARS MORE THAN TWICE OF HER SISTER'S AGE. WHAT ARE THEIR PRESENT AGE? THANK U VERY MUCH...
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Algebra.Com's Answer #95570 by checkley71(8403)\"\" \"About 
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JANE=3X
\n" ); document.write( "SISTER=X
\n" ); document.write( "(3X+3)=2(X+3)+2
\n" ); document.write( "3X+3=2X+6+2
\n" ); document.write( "3X-2X=6+2-3
\n" ); document.write( "X=5 AGE OF THE SISTER NOW.
\n" ); document.write( "3*5=15 JANE'S AGE NOW.PROOF:
\n" ); document.write( "(3*5+3)=2(5+3)+2
\n" ); document.write( "15+3=2*8+2
\n" ); document.write( "18=16+2
\n" ); document.write( "18=18
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