document.write( "Question 130933: Solve for r.\r
\n" ); document.write( "\n" ); document.write( "r^2 + 3r = 5.\r
\n" ); document.write( "\n" ); document.write( "The solutions are r = ________.\r
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Algebra.Com's Answer #95558 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
R^2+3R=5
\n" ); document.write( "R^2+3R-5=0
\n" ); document.write( "USING THE QUADRATIC EQUATION:
\n" ); document.write( "\"R%5E2%2B3R=5%0D%0AR%5E2%2B3R-5=0%0D%0AUSING+THE+QUADRATIC+EQUATION%3A%0D%0A\"R = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}
\n" ); document.write( "R=(-3+-SQRT[3^3-4*1*5])/1*2
\n" ); document.write( "R=(-3+-SQRT[9-20])/2
\n" ); document.write( "R=(-3+-SQRT29)/2
\n" ); document.write( "R=(-3+-5.385)/2
\n" ); document.write( "R=(-3+5.385)/2
\n" ); document.write( "R=2.385/2
\n" ); document.write( "R=1.19 ANSWER.
\n" ); document.write( "R=(-3-5.385)/2
\n" ); document.write( "R=-8.385/2
\n" ); document.write( "R=-4.19 ANSWER.
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