document.write( "Question 130767: Solve x^2 + 7x -2 = 0\r
\n" ); document.write( "\n" ); document.write( "And, then find the x-intercepts of f(x) = x^2 + 7x - 2.\r
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Algebra.Com's Answer #95489 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
# 1\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for x:\r
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\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"x%5E2%2B7%2Ax-2=0\" ( notice \"a=1\", \"b=7\", and \"c=-2\")\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-7+%2B-+sqrt%28+%287%29%5E2-4%2A1%2A-2+%29%29%2F%282%2A1%29\" Plug in a=1, b=7, and c=-2\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-7+%2B-+sqrt%28+49-4%2A1%2A-2+%29%29%2F%282%2A1%29\" Square 7 to get 49 \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-7+%2B-+sqrt%28+49%2B8+%29%29%2F%282%2A1%29\" Multiply \"-4%2A-2%2A1\" to get \"8\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-7+%2B-+sqrt%28+57+%29%29%2F%282%2A1%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-7+%2B-+sqrt%2857%29%29%2F2\" Multiply 2 and 1 to get 2\r
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\n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-7+%2B+sqrt%2857%29%29%2F2\" or \"x+=+%28-7+-+sqrt%2857%29%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "So these expressions approximate to\r
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\n" ); document.write( "\n" ); document.write( "\"x=0.274917217635375\" or \"x=-7.27491721763537\"\r
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\n" ); document.write( "\n" ); document.write( "So our solutions are:\r
\n" ); document.write( "\n" ); document.write( "\"x=0.274917217635375\" or \"x=-7.27491721763537\"\r
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\n" ); document.write( "\n" ); document.write( "Notice when we graph \"x%5E2%2B7%2Ax-2\", we get:\r
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\n" ); document.write( "\n" ); document.write( "when we use the root finder feature on a calculator, we find that \"x=0.274917217635375\" and \"x=-7.27491721763537\".So this verifies our answer\r
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