document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=130778>Question 130778</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Determining a Necessary Grade: A mean average of 80 or greater for five exams is needed for a final grade of B. Jorge Rivera's first four exam grades are 73, 69, 85, and 80. What grade does Jorge need on the fifth exam to get a B in the course? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #95486 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=95486\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (73+69+85+80+x)/5>=80<BR>\n" );
document.write( "(307+x)/5>=80 now cross multiply.<BR>\n" );
document.write( "307+x>=5*80<BR>\n" );
document.write( "307+x>=400<BR>\n" );
document.write( "x>=400-307<BR>\n" );
document.write( "x>=93 is the score needed to maintian an 80 average. </SPAN>\n" );
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