document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=130764>Question 130764</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve by completing the square.\r<BR>\n" );
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document.write( "x^2 - 16x = 10\r<BR>\n" );
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document.write( "I tried using one of the solvers and it didn't seem to work for this problem. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #95473 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=95473\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2-16x=10<BR>\n" );
document.write( "x^2-16x+64=10+64 take (-16/2=-8) and square it (64) and use it as the third number. (completing the square. <BR>\n" );
document.write( "(x-8)^2=74<BR>\n" );
document.write( "x-8=+-sqrt(74) Sqrt of both sides<BR>\n" );
document.write( "x=8+-sqrt(74)<BR>\n" );
document.write( "x=8+sqrt(74), x=8-sqrt(74)<BR>\n" );
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document.write( "Ed\r<BR>\n" );
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document.write( " </SPAN>\n" );
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