document.write( "Question 130754: Find the vertex and line of symmetry\r
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\n" ); document.write( "\n" ); document.write( " $\"f%28x%29=%28x%2B2%29%5E2\"$ \n" ); document.write( "

Algebra.Com's Answer #95465 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Since $\"f%28x%29=%28x%2B2%29%5E2\"$ is in vertex form $\"y=a%28x-h%29%5E2%2Bk\"$ where a is the stretch/compression factor and (h,k) is the vertex, this means that h=-2 and k=0 (note: $\"f%28x%29=%28x%2B2%29%5E2\"$ really looks like $\"f%28x%29=1%28x-%28-2%29%29%5E2%2B0\"$ )\r
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\n" ); document.write( "\n" ); document.write( "So the vertex is (-2,0)\r
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\n" ); document.write( "\n" ); document.write( "Also, the line of symmetry is simply the equation $\"x=h\"$ . So in this case the line of symmetry is $\"x=-2\"$ \r
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\n" ); document.write( "\n" ); document.write( "If we graph, we can visually verify our answer.\r
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Graph of $\"f%28x%29=%28x%2B2%29%5E2\"$ with a vertex of (-2,0) and the line of symmetry of $\"x=-2\"$
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