document.write( "Question 130742This question is from textbook Algrebra II
\n" ); document.write( ": \"%285-x%29%5E%281%2F2%29-1=x\" \n" ); document.write( "
Algebra.Com's Answer #95460 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
You don't actually say, but I'll presume that you need to solve this equation for x.\r
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\n" ); document.write( "\n" ); document.write( "\"%285-x%29%5E%281%2F2%29-1=x\"\r
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\n" ); document.write( "\n" ); document.write( "Remember that \"a%5E%281%2F2%29=sqrt%28a%29\", so your equation becomes:\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%285-x%29-1=x\"\r
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\n" ); document.write( "\n" ); document.write( "Add 1 to both sides:\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%285-x%29=x%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "Square both sides:\r
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\n" ); document.write( "\n" ); document.write( "\"5-x=x%5E2%2B2x%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "Put the equation in standard form \"ax%5E2%2Bbx%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"-x%5E2-2x-1%2B5-x=0\"
\n" ); document.write( "\"-x%5E2-3x%2B4=0\"\r
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\n" ); document.write( "\n" ); document.write( "Multiply by -1:\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B3x-4=0\"\r
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\n" ); document.write( "\n" ); document.write( "Since \"4%2A-1=-4\" and \"4-1=3\", this quadratic factors to:\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B4%29%28x-1%29=0\",\r
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\n" ); document.write( "\n" ); document.write( "Therefore \"x=-4\" or \"x=1\". However, since this is a radical equation (meaning that the variable is under a radical sign), there is a possibility that by squaring both sides of the equation, we may have derived an equation that is not exactly equivalent to the original and have introduced an extraneous root.\r
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\n" ); document.write( "\n" ); document.write( "Check the answers:\r
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\n" ); document.write( "\n" ); document.write( "\"%285-1%29%5E%281%2F2%29-1=1\"
\n" ); document.write( "\"%284%29%5E%281%2F2%29-1=1\"
\n" ); document.write( "\"2-1=1\": True statement. \"x=1\" is in the solution set.\r
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\n" ); document.write( "\n" ); document.write( "\"%285-%28-4%29%29%5E%281%2F2%29-1=-4\"
\n" ); document.write( "\"%289%29%5E%281%2F2%29-1=-4\"
\n" ); document.write( "\"3-1=2%3C%3E-4\": False statement. \"x=-4\" is NOT in the solution set.\r
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\n" ); document.write( "\n" ); document.write( "\"x=1\", and that's my final answer, Regis.
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