document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=130686>Question 130686</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the domain of x-2y=1 if the range is (-2,0,5,8,) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #95453 by </B><A HREF=/tutors/aboutme.mpl?userid=cngriffith><B>cngriffith(27)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cngriffith><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=95453\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The domain is the x value. The range is the y value.  Alphabeticly domain comes before range.   Alphabaticly, x comes before y.   Therefore x=domain and y= range.\r<BR>\n" );
document.write( "\n" );
document.write( "x-2y=1<BR>\n" );
document.write( "x=2y+1   Solve equation for x.<BR>\n" );
document.write( "x=2(-2) +1<BR>\n" );
document.write( "x=-4+1=-3    Substitute the first value in the range for y and solve for x.<BR>\n" );
document.write( "             Continue this process for each number in the range.<BR>\n" );
document.write( "x=2(0)+1<BR>\n" );
document.write( "x=1\r<BR>\n" );
document.write( "\n" );
document.write( "x=2(5)+1<BR>\n" );
document.write( "x=11\r<BR>\n" );
document.write( "\n" );
document.write( "x=2(8)=1<BR>\n" );
document.write( "x=17<BR>\n" );
document.write( "Domain is -3,1,11,17   </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );