document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=130705>Question 130705</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A  can do a piece of work in 25 days and B can do a work in 20 days.both work together for 5days after that a leaves. how long will B need to finish the remaining work. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #95447 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=95447\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x= amount of time it will take B to finish the job<BR>\n" );
document.write( "A works at the rate of 1/25 of the job per day<BR>\n" );
document.write( "B works at the rate of 1/20 of the job per day\r<BR>\n" );
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document.write( "Together A & B work at the rate of 1/25  +  1/20=<BR>\n" );
document.write( "4/100 + 5/100= 9/100 of the job per day\r<BR>\n" );
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document.write( "If they both work together for 5 days, they complete (9/100)*5 or <BR>\n" );
document.write( "45/100 of the job, leaving 55/100 of the job yet to be done\r<BR>\n" );
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document.write( "B can do 1/20 of the job per day, so:\r<BR>\n" );
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document.write( "(1/20)*x=55/100  multiply each side by 100<BR>\n" );
document.write( "5x=55  divide both sides by 5<BR>\n" );
document.write( "x=11 days-----------------amount of time needed by B to finish the job\r<BR>\n" );
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document.write( "Hope this helps---ptaylor<BR>\n" );
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