document.write( "Question 130618This question is from textbook
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document.write( ": Please help me solve this equation: melinda's dad is 30 years older than melinda is now. eight years ago, his age was equal to the square of melinda's age then. how old is melinda now? \n" );
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Algebra.Com's Answer #95446 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=Melinda's age now; x-8=Melinda's age 8 years ago\r \n" ); document.write( "\n" ); document.write( "Then x+30=Melinda's dad's age now; x+30-8=x+22=dad's age 8 years ago\r \n" ); document.write( "\n" ); document.write( "Now we are told that:\r \n" ); document.write( "\n" ); document.write( "x+22=(x-8)^2 get rid of parens\r \n" ); document.write( "\n" ); document.write( "x+22=x^2-16x+64 subtract x and also 22 from each side\r \n" ); document.write( "\n" ); document.write( "x-x+22-22=x^2-16x-x+64-22 collect like terms\r \n" ); document.write( "\n" ); document.write( "x^2-17x+42=0--------------------quadratic in standard form and it can be factored\r \n" ); document.write( "\n" ); document.write( "(x-3)(x-14)=0\r \n" ); document.write( "\n" ); document.write( "x=3 years old (NO GOOD!!! 8 YEARS AGO SHE WOULD BE -5????) \n" ); document.write( "and x=14 years old-----------------Melinda's age now\r \n" ); document.write( "\n" ); document.write( "x+30=14+30=44 years old her dad's age now\r \n" ); document.write( "\n" ); document.write( "CK\r \n" ); document.write( "\n" ); document.write( "8 years ago dad's age was equal to the square of Melinda's-- \n" ); document.write( "44-8=(14-8)^2\r \n" ); document.write( "\n" ); document.write( "36=6^2 \n" ); document.write( "36=36\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |