document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=130703>Question 130703</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help setting this problem up please... The question reads: \"Two trains, an express and a commuter , are 150 miles apart. Both start at the same time and travel toward each other. They meet 3 hours later. The speed of the express is 10 miles faster than the commuter. Find the speed of each train.\"   Thanks for you help!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #95444 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=95444\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
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document.write( "Distance(d) equals Rate(r) times Time(t)or d=rt; r=d/t and t=d/r\r<BR>\n" );
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document.write( "Let r=speed of the commuter <BR>\n" );
document.write( "Then r+10=speed of the express\r<BR>\n" );
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document.write( "distance commuter travels=rt=r*3 or 3r<BR>\n" );
document.write( "distance express travels=rt=(r+10)*3 or 3r+30\r<BR>\n" );
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document.write( "Now we are told that the above two distances add up to 150 mi, so:\r<BR>\n" );
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document.write( "3r+3r+30=150  Can you handle it from here???\r<BR>\n" );
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document.write( "Hope this helps---ptaylor\r<BR>\n" );
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