document.write( "Question 130636This question is from textbook ALGEBRA 2
\n" ); document.write( ": IN MY ALGEBRA 2 BOOK ON PAGE 296 I'M HAVING A HARD TIME UNDERSTANDING HOW I FIND THE SOLUTION. THE SOLUTION FUNCITON IS, X=-b+ - SQUARE UNDER b SQ. 2 -4ac/2a.okay now how do I fiqure out the solution? I'm stuck at this p.for ex.x sq.2 minus 4x + 10=0,using the discriminant function i've got ( -4)sq.2 -4(1)(10)=24.i know how to set the solution function up (X=-b+ - SQUARE UNDER b SQ. 2 -4ac/2a) x=-4+ - sq.root4 sq.2 minus 4(1)(10). now where do i go from there.i don't understand how to first solve it. do i use a calculator for that part or not?
\n" ); document.write( "well I reallywould appreciate if you can help me out with my problem , it would mean alot to me, since my test on this is on friday, at my school!
\n" ); document.write( "thanks! \n" ); document.write( "

Algebra.Com's Answer #95421 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Solve for $\"x%5E2-4x%2B10+=+0\"$ x using the quadratic formula: $\"x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a\"$ Make the appropriate substitutions of a = 1, b = -4, and c = 10.
\n" ); document.write( " $\"x+=+%28-%28-4%29%2B-sqrt%28%28-4%29%5E2-4%281%29%2810%29%29%29%2F2%281%29\"$
\n" ); document.write( " $\"x+=+%284%2B-sqrt%2816-40%29%29%2F2\"$
\n" ); document.write( " $\"x+=+%284%2B-sqrt%28-24%29%29%2F2\"$
\n" ); document.write( " $\"x+=+%284%2B-sqrt%28-4%2A6%29%29%2F2\"$
\n" ); document.write( " $\"x+=+4%2F2%2B2%2Asqrt%28-6%29%2F2\"$ or $\"x+=+4%2F2+-+2%2Asqrt%28-6%29%2F2\"$ Simplify.
\n" ); document.write( " $\"x+=+2%2Bsqrt%286%29i\"$ or $\"x+=+2-sqrt%286%29i\"$ \n" ); document.write( "

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