document.write( "Question 19722: 12(x+3)2=7488 \n" ); document.write( "
Algebra.Com's Answer #9541 by Alwayscheerful(414)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: EXPLAIN simplification of an expression
Your Result:

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  • This is an equation! Solutions: x=205.
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  • Graphical form: Equation \"12%2A3%2A%28x%2B3%29=7488\" was fully solved.
  • Text form: 12*3*(x+3)=7488 simplifies to 0=0
  • Cartoon (animation) form: \"simplify_cartoon%28+12%2A3%2A%28x%2B3%29=7488+%29\"
    For tutors: simplify_cartoon( 12*3*(x+3)=7488 )
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  • If you have a website, here's a link to this solution.
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DETAILED EXPLANATION

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Look at \"highlight_red%28+12+%29%2Ahighlight_red%28+3+%29%2A%28x%2B3%29=7488\".
Multiplied numerator integers
It becomes \"highlight_green%28+36+%29%2A%28x%2B3%29=7488\".
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Look at \"36%2A%28x%2B3%29=highlight_red%28+7488+%29\".
Moved these terms to the left \"highlight_green%28+-7488+%29\"
It becomes \"36%2A%28x%2B3%29-highlight_green%28+7488+%29=0\".
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Look at \"highlight_red%28+36%2A%28x%2B3%29+%29-7488=0\".
Expanded term \"36\" by using associative property on \"%28x%2B3%29\"
It becomes \"highlight_green%28+36%2Ax+%29%2Bhighlight_green%28+36%2A3+%29-7488=0\".
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Look at \"36%2Ax%2Bhighlight_red%28+36+%29%2Ahighlight_red%28+3+%29-7488=0\".
Multiplied numerator integers
It becomes \"36%2Ax%2Bhighlight_green%28+108+%29-7488=0\".
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Look at \"36%2Ax%2Bhighlight_red%28+108+%29-highlight_red%28+7488+%29=0\".
Added fractions or integers together
It becomes \"36%2Ax%2Bhighlight_green%28+-7380+%29=0\".
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Look at \"36%2Ax%2Bhighlight_red%28+-7380+%29=0\".
Removed extra sign in front of \"-7380\"
It becomes \"36%2Ax-highlight_green%28+7380+%29=0\".
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Look at \"highlight_red%28+36%2Ax-7380+%29=0\".
Solved linear equation \"highlight_red%28+36%2Ax-7380=0+%29\" equivalent to 36*x-7380 =0
It becomes \"highlight_green%28+0+%29=0\".
Result: \"0=0\"
\n" ); document.write( "This is an equation! Solutions: x=205.

Universal Simplifier and Solver

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Done!

\n" ); document.write( "\n" ); document.write( "If you need further assistance, I can answer questions by email (probably $1 per question) will full detail and explanation.
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