document.write( "Question 130639: What is the base b of the function \"f%28x%29=b%5Ex\" if \"f%28-2%29=1%2F64\" \n" ); document.write( "
Algebra.Com's Answer #95403 by jim_thompson5910(35256)\"\" \"About 
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\"f%28x%29=b%5Ex\" Start with the given function\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F64=b%5E%28-2%29\" Plug in x=-2 and \"f%28-2%29=1%2F64\"\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F64=1%2Fb%5E2\" Rewrite \"b%5E%28-2%29\" as \"1%2Fb%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"b%5E2=64\" Cross multiply\r
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\n" ); document.write( "\n" ); document.write( "\"b=sqrt%2864%29\" Take the square root of both sides\r
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\n" ); document.write( "\n" ); document.write( "\"b=8\" Take the square root of 64 to get 8 \r
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\n" ); document.write( "\n" ); document.write( "So the function is \"f%28x%29=8%5Ex\"
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