document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=130631>Question 130631</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the graph of  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=f%28x%29=b%5Ex ALIGN=MIDDLE  ALT=\"f%28x%29=b%5Ex\"   DISABLED_style= \"max-width:90%; height:auto;\" > asses through the point (2,9), find f(4) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #95401 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=95401\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since the graph passes through the point (2,9), this means that when x=2, then y=9. \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=b%5Ex ALIGN=MIDDLE  ALT=\"y=b%5Ex\"   DISABLED_style= \"max-width:90%; height:auto;\" > Start with the given equation\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=9=b%5E2 ALIGN=MIDDLE  ALT=\"9=b%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Plug in x=2 and y=9. Notice how the only unknown left is b\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%289%29=sqrt%28b%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%289%29=sqrt%28b%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Take the square root of both sides to isolate b\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%289%29=b ALIGN=MIDDLE  ALT=\"sqrt%289%29=b\"   DISABLED_style= \"max-width:90%; height:auto;\" > Take the square root of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5E2 ALIGN=MIDDLE  ALT=\"b%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > to get b\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b=3 ALIGN=MIDDLE  ALT=\"b=3\"   DISABLED_style= \"max-width:90%; height:auto;\" > Take the square root of 9 to get 3 \r<BR>\n" );
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document.write( "So our equation becomes \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=3%5Ex ALIGN=MIDDLE  ALT=\"y=3%5Ex\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Now to evaluate f(4), simply plug in x=4\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=3%5E4 ALIGN=MIDDLE  ALT=\"y=3%5E4\"   DISABLED_style= \"max-width:90%; height:auto;\" > Plug in x=4\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=81 ALIGN=MIDDLE  ALT=\"y=81\"   DISABLED_style= \"max-width:90%; height:auto;\" > Evaluate 3 to the fourth power to get 81\r<BR>\n" );
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document.write( "Since \"y\" is equivalent to f(x), this means that <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=f%284%29=81 ALIGN=MIDDLE  ALT=\"f%284%29=81\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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