document.write( "Question 130626: Solve for x: \"5%2A6%5E%282x-3%29%2B1=8\" \n" ); document.write( "
Algebra.Com's Answer #95396 by jim_thompson5910(35256)\"\" \"About 
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\"5%2A6%5E%282x-3%29%2B1=8\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"5%2A6%5E%282x-3%29=7\" Subtract 1 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"6%5E%282x-3%29=7%2F5\" Divide both sides by 5\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%286%5E%282x-3%29%29%29=log%2810%2C%287%2F5%29%29\" Take the log of both sides\r
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\n" ); document.write( "\n" ); document.write( "\"%282x-3%29log%2810%2C%286%29%29=log%2810%2C%287%2F5%29%29\" Rewrite the left side using the identity \"log%28b%2C%28x%5Ey%29%29=y%2Alog%28b%2C%28x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x-3=log%2810%2C%287%2F5%29%29%2Flog%2810%2C%286%29%29\" Divide both sides by \"log%2810%2C%286%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x-3=log%286%2C%287%2F5%29%29\" Now use the change of base formula to simplify \"log%2810%2C%287%2F5%29%29%2Flog%2810%2C%286%29%29\" to get \"log%286%2C%287%2F5%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x=log%286%2C%287%2F5%29%29%2B3\" Add 3 to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28log%286%2C%287%2F5%29%29%2B3%29%2F2\" Divide both sides by 2 to isolate x
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