document.write( "Question 130624: Factor the trinomial \"x%5E2+-+2x+%2B+1\". \n" ); document.write( "
Algebra.Com's Answer #95393 by jim_thompson5910(35256)\"\" \"About 
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Looking at \"x%5E2-2x%2B1\" we can see that the first term is \"x%5E2\" and the last term is \"1\" where the coefficients are 1 and 1 respectively.\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient 1 and the last coefficient 1 to get 1. Now what two numbers multiply to 1 and add to the middle coefficient -2? Let's list all of the factors of 1:\r
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\n" ); document.write( "\n" ); document.write( "Factors of 1:\r
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\n" ); document.write( "\n" ); document.write( "-1 ...List the negative factors as well. This will allow us to find all possible combinations\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to 1\r
\n" ); document.write( "\n" ); document.write( "1*1\r
\n" ); document.write( "\n" ); document.write( "(-1)*(-1)\r
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\n" ); document.write( "\n" ); document.write( "note: remember two negative numbers multiplied together make a positive number\r
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\n" ); document.write( "\n" ); document.write( "Now which of these pairs add to -2? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -2\r
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First NumberSecond NumberSum
111+1=2
-1-1-1+(-1)=-2
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\n" ); document.write( "\n" ); document.write( "From this list we can see that -1 and -1 add up to -2 and multiply to 1\r
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\n" ); document.write( "\n" ); document.write( "Now looking at the expression \"x%5E2-2x%2B1\", replace \"-2x\" with \"-x-x\" (notice \"-x-x\" adds up to \"-2x\". So it is equivalent to \"-2x\")\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bhighlight%28-x-x%29%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's factor \"x%5E2-x-x%2B1\" by grouping:\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2-x%29%2B%28-x%2B1%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x-1%29-1%28x-1%29\" Factor out the GCF of \"x\" out of the first group. Factor out the GCF of \"-1\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-1%29%28x-1%29\" Since we have a common term of \"x-1\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"x%5E2-x-x%2B1\" factors to \"%28x-1%29%28x-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "So this also means that \"x%5E2-2x%2B1\" factors to \"%28x-1%29%28x-1%29\" (since \"x%5E2-2x%2B1\" is equivalent to \"x%5E2-x-x%2B1\")\r
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\n" ); document.write( "\n" ); document.write( "note: \"%28x-1%29%28x-1%29\" is equivalent to \"%28x-1%29%5E2\" since the term \"x-1\" occurs twice. So \"x%5E2-2x%2B1\" also factors to \"%28x-1%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( " Answer:\r
\n" ); document.write( "\n" ); document.write( "So \"x%5E2-2x%2B1\" factors to \"%28x-1%29%5E2\"
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